Дано:
$m_1=200g$
$C_1=920 \frac{Dg}{кg*C}$
$V_2=1,5l$
$C_2=4200 \frac{Dg}{кg*C}$
$p_2=1000 \frac{g}{cm^3}$
$t_1=20C$
$t_2=100C$
$-$
$Q-$

Решение:
$Q=Q_1+Q_2$
$Q_1=C_1m_1(t_2-t_1)$
$Q_2=C_2m_2(t_2-t_1)$
$m_1=200g=0,2кg$
$V_2=1,5l=0,0015m^3$
$m_2=p_2V_2$
$m_2=1000 \frac{g}{cm^3}*0,0015m^3=1,5кg$
$Q_1=920 \frac{Dg}{кg*C} *0,2кg*(100C-20C)=14720Dg$
$Q_2=4200 \frac{Dg}{кg}*1,5кg*(100C-20C)= 504000Dg$
$Q=14720Dg+504000Dg=518720Dg$

Ответ: $Q=518720Dg$